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Location: New Mexico
Joined: 07/08/2008
Posts: 84
How much does the atmosphere magnify an object at distance?

After reading Kevins article on judging pronghorns, it got me thinking about experiences i have had with clients and myself being fooled by the size of a buck because of atmospheric magnification. So I was curious if anyone could take a stab at what that number may be. I will take first crack at it.

At first light is seems to be less of an effect so i would guess 1% for every 100 yards. So thats 10% at 1000 yards.
.

At mid day, its much worse (heat waves?), I would guess 2% for every 100 yards. So thats 20% at 1000 yards. I think thats pretty close but not sure.

Can anyone add some intellegence to this??

Offline
Location: Alberta
Joined: 08/24/2008
Posts: 94
How much does the atmosphere magnify an object at distance?

I think high atmospheric pressure would affect this as well, not sure which way though.

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Location: New Mexico
Joined: 07/08/2008
Posts: 84
How much does the atmosphere magnify an object at distance?

Most certainly, so altitude is a factor then..

ndemiter's picture
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Grand Slam Challenge Winner!
Location: lawrence, KS
Joined: 05/17/2007
Posts: 647
http://www.encyclopedia-titan

http://www.encyclopedia-titanica.org/discus/messages/5666/113052.html?1154622528

read this one.

my answer to your question about magnification is that it depends on the distance, the air pressure and layering of different temperatures in the atmosphere at the time.

the amounts of "mirage" vary with all of these factors. your best bet is to try to not compenstae for it and just get a closer look.

it's truly a complicated endeavor!

ndemiter's picture
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Location: lawrence, KS
Joined: 05/17/2007
Posts: 647
okay, you really got me

okay, you really got me thinking about it. so i decided to come up with an equation to figure this problem out.

the problem is... is that it's a series of equations.

 

wavelength (l)

difraction (d)

air preassure (possibly an initial and a final such as Pf-Pi=Pvariance)

air temperature (t)

diameter of the aperature you're looking through (Da)

altitude (A)

Humidity (H)

but simply, with out all of these correctional factors, you're looking at the difference between the angle of incidence of a wave at a certain distance.

so  

(l*q)-(l*q)(D

 

D)

and you know what. i spent an hour behind my physics books trying to figure this out... and i probably completely wasted that hour of my life because it almost seems like i need to devide this equation by another measurement in order to come oout with the right units.

it could take a good physicist years to figure this out.

infact, forget i even mentioned it. i'm going to gbed and am going to read through my horse catalog and try to recover from the feeling of wasted life i just succumed to.

and GREAT, in the preview, the forum wont even recognize all the greek letters in this deal.

i'm going to bed, and if you're curios about exactly what look is on my face right now... it's defeat!

hunter25's picture
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Grand Slam Challenge Winner!
Location: Colorado western slope
Joined: 11/13/2009
Posts: 3021
I agree with getting closer

I agree with getting closer as this is just too much to worry about and try to calculate. If you are close enought to make an ethical shot then you should easily be able to judge if the quality of the headgear is what you are looking for.

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